Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 5667    Accepted Submission(s): 2681

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;

Now please try your lucky.

 

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

 

Sample Input

2 100 -4

 

 

Sample Output

1.6152 No solution!

 

 

Author

Redow

 

 

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代码：

#include
      
       #include
       
        #define sum(x) ((8*x*x*x*x)+(7*x*x*x)+(2*x*x)+(3*x)+(6))using namespace std;int main(){    int t;    double y,mid,left,right;    cin>>t;    while(t--)    {     scanf("%lf",&y);     left=0.0,right=100.0;     if(y>=6.0&&y<=sum(100))     {      while(right-left>1e-8)      {         mid=(left+right)/2.0;             if(sum(mid)-y>1e-8)             right=mid;         else             if(y-sum(mid)>1e-8)                 left=mid;             else                  break;      }          printf("%.4lf\n",mid);     }     else         puts("No solution!");    }    return 0;}